Optimal. Leaf size=287 \[ \frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{b d+2 c d x}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right ),-1\right )}{5 c d^{7/2} \left (b^2-4 a c\right )^{5/4} \sqrt{a+b x+c x^2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 d^3 \left (b^2-4 a c\right )^2 \sqrt{b d+2 c d x}}-\frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\right |-1\right )}{5 c d^{7/2} \left (b^2-4 a c\right )^{5/4} \sqrt{a+b x+c x^2}}+\frac{4 \sqrt{a+b x+c x^2}}{5 d \left (b^2-4 a c\right ) (b d+2 c d x)^{5/2}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.248231, antiderivative size = 287, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {693, 691, 690, 307, 221, 1199, 424} \[ \frac{12 \sqrt{a+b x+c x^2}}{5 d^3 \left (b^2-4 a c\right )^2 \sqrt{b d+2 c d x}}+\frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\right |-1\right )}{5 c d^{7/2} \left (b^2-4 a c\right )^{5/4} \sqrt{a+b x+c x^2}}-\frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\right |-1\right )}{5 c d^{7/2} \left (b^2-4 a c\right )^{5/4} \sqrt{a+b x+c x^2}}+\frac{4 \sqrt{a+b x+c x^2}}{5 d \left (b^2-4 a c\right ) (b d+2 c d x)^{5/2}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 693
Rule 691
Rule 690
Rule 307
Rule 221
Rule 1199
Rule 424
Rubi steps
\begin{align*} \int \frac{1}{(b d+2 c d x)^{7/2} \sqrt{a+b x+c x^2}} \, dx &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{3 \int \frac{1}{(b d+2 c d x)^{3/2} \sqrt{a+b x+c x^2}} \, dx}{5 \left (b^2-4 a c\right ) d^2}\\ &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right )^2 d^3 \sqrt{b d+2 c d x}}-\frac{3 \int \frac{\sqrt{b d+2 c d x}}{\sqrt{a+b x+c x^2}} \, dx}{5 \left (b^2-4 a c\right )^2 d^4}\\ &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right )^2 d^3 \sqrt{b d+2 c d x}}-\frac{\left (3 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \int \frac{\sqrt{b d+2 c d x}}{\sqrt{-\frac{a c}{b^2-4 a c}-\frac{b c x}{b^2-4 a c}-\frac{c^2 x^2}{b^2-4 a c}}} \, dx}{5 \left (b^2-4 a c\right )^2 d^4 \sqrt{a+b x+c x^2}}\\ &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right )^2 d^3 \sqrt{b d+2 c d x}}-\frac{\left (6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1-\frac{x^4}{\left (b^2-4 a c\right ) d^2}}} \, dx,x,\sqrt{b d+2 c d x}\right )}{5 c \left (b^2-4 a c\right )^2 d^5 \sqrt{a+b x+c x^2}}\\ &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right )^2 d^3 \sqrt{b d+2 c d x}}+\frac{\left (6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-\frac{x^4}{\left (b^2-4 a c\right ) d^2}}} \, dx,x,\sqrt{b d+2 c d x}\right )}{5 c \left (b^2-4 a c\right )^{3/2} d^4 \sqrt{a+b x+c x^2}}-\frac{\left (6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname{Subst}\left (\int \frac{1+\frac{x^2}{\sqrt{b^2-4 a c} d}}{\sqrt{1-\frac{x^4}{\left (b^2-4 a c\right ) d^2}}} \, dx,x,\sqrt{b d+2 c d x}\right )}{5 c \left (b^2-4 a c\right )^{3/2} d^4 \sqrt{a+b x+c x^2}}\\ &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right )^2 d^3 \sqrt{b d+2 c d x}}+\frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\right |-1\right )}{5 c \left (b^2-4 a c\right )^{5/4} d^{7/2} \sqrt{a+b x+c x^2}}-\frac{\left (6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+\frac{x^2}{\sqrt{b^2-4 a c} d}}}{\sqrt{1-\frac{x^2}{\sqrt{b^2-4 a c} d}}} \, dx,x,\sqrt{b d+2 c d x}\right )}{5 c \left (b^2-4 a c\right )^{3/2} d^4 \sqrt{a+b x+c x^2}}\\ &=\frac{4 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right ) d (b d+2 c d x)^{5/2}}+\frac{12 \sqrt{a+b x+c x^2}}{5 \left (b^2-4 a c\right )^2 d^3 \sqrt{b d+2 c d x}}-\frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} E\left (\left .\sin ^{-1}\left (\frac{\sqrt{b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\right |-1\right )}{5 c \left (b^2-4 a c\right )^{5/4} d^{7/2} \sqrt{a+b x+c x^2}}+\frac{6 \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac{\sqrt{b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\right |-1\right )}{5 c \left (b^2-4 a c\right )^{5/4} d^{7/2} \sqrt{a+b x+c x^2}}\\ \end{align*}
Mathematica [C] time = 0.0613787, size = 91, normalized size = 0.32 \[ -\frac{2 \sqrt{\frac{c (a+x (b+c x))}{4 a c-b^2}} \, _2F_1\left (-\frac{5}{4},\frac{1}{2};-\frac{1}{4};\frac{(b+2 c x)^2}{b^2-4 a c}\right )}{5 c d \sqrt{a+x (b+c x)} (d (b+2 c x))^{5/2}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.258, size = 874, normalized size = 3.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (2 \, c d x + b d\right )}^{\frac{7}{2}} \sqrt{c x^{2} + b x + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{2 \, c d x + b d} \sqrt{c x^{2} + b x + a}}{16 \, c^{5} d^{4} x^{6} + 48 \, b c^{4} d^{4} x^{5} + a b^{4} d^{4} + 8 \,{\left (7 \, b^{2} c^{3} + 2 \, a c^{4}\right )} d^{4} x^{4} + 32 \,{\left (b^{3} c^{2} + a b c^{3}\right )} d^{4} x^{3} + 3 \,{\left (3 \, b^{4} c + 8 \, a b^{2} c^{2}\right )} d^{4} x^{2} +{\left (b^{5} + 8 \, a b^{3} c\right )} d^{4} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (d \left (b + 2 c x\right )\right )^{\frac{7}{2}} \sqrt{a + b x + c x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (2 \, c d x + b d\right )}^{\frac{7}{2}} \sqrt{c x^{2} + b x + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]